So welcome to our today's lecture on the finite element method. First of all let me
a little bit summarize what we did last time and this I will do with help of
the notes of last time. If you remember we provided the element wise approximation
of the derivatives of the solution and the test function. This is done in the
similar way like the approximation of the geometry and furthermore we figured
out that we have a derivative of the shape function which is a function of
the local coordinate with respect to the global coordinates and here comes the
derivative due to the chain rule of the local coordinates with respect to the
global coordinates in which is here just the inverse of the Jacobian and
eventually we ended up with this approximation of the derivative of the
solution and same for the derivative of the test function. The similarity with
the approximation of the geometry is obvious here. We started here with this
approximation of the solution and of the test function and these are the same
like the approximation of the geometry. Then we inserted that into the
formulation for an entry for the stiffness matrix and we figured out
that we can have the same format for all elements except the inverse of the
Jacobian brings in the relation between the local and global coordinates
which is in general different for each element. Then we did some examples to
demonstrate that and after that we had a look to the entries of the force vector
which works similarly and when it comes to the force vector we have here the
distributed load either the G or the N in and to provide here a formulation local
coordinates used again the same approximation like for the geometry for
the solution and for the test function. Then we also did some computations we
will come back to that in today's tutorial there we will derive the
stiffness matrix entries for a quadratic element. So after that we considered
numerical integration and we focused first on a very simple approach the
rectangle method then the Newton-Cotes quadrature where we have certain
combinations of quadrature points positions and weights and we also
derived or actually we discussed what polynomials of which degree can be
integrated exactly by using the Newton-Cotes integration and here is once
again given the rule for that. Today I would like to continue here and come
for a short time back to the Newton-Cotes quadrature but first the
question to you is there anything we should discuss of last time? Did you
figure out any issues? So in an examination you could be asked for let's
say please integrate this polynomial using Newton-Cotes or Gauss quadrature so
it is relevant. So when it comes to Newton-Cotes we have actually we have
the same setup for all these quadrature rules and here it is specifically given
for Newton-Cotes because here we have the number of Newton-Cotes points and we
always have a combination. First we have to have this interval from minus
one to one. The finite element framework this is given because we always have
this interval chosen for the local coordinates. So and then we have the
summation over the Newton-Cotes quadrature points and we have to evaluate
our function which we want to integrate so the argument of our integration. This
we have to evaluate at the specific quadrature point and multiply that with
the associated weight. So for instance when we choose one quadrature point then
we have to evaluate f at zero with a weight of two. When we have two points
then we have to evaluate the function at minus one and one with a weight of
one each. So and then you can have more and more quadrature points. Yes, yes.
So that should answer your question. Okay so then let us come back today briefly to this choice
Newton-Cotes with two quadrature points.
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01:27:37 Min
Aufnahmedatum
2024-05-07
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2024-05-09 02:19:34
Sprache
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